題目:
∫1/√x-x²dx應該怎麼求?
解答:
x-x²=1/4-1/4+x-x²=1/4-(x-1/2)^2原來的積分化爲∫1/√x-x²=∫d(2x-1)/√[1-(2x-1)^2]=arcsin(2x-1)+c
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